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Mashukkk
@Mashukkk
July 2022
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Найти первообразную от функции f(x)=4-x², график проходит через точку (-3;10)
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yarovoe
f(x)=4-x², A(-3:10)
F(x)=4x-x
³/3+C, F(-3)=4·(-3)-(-3)³/3+C=10
-12+9+C=10,C=10+12-9=13
F(x)=4x-x³/3+13
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Answers & Comments
F(x)=4x-x³/3+C, F(-3)=4·(-3)-(-3)³/3+C=10
-12+9+C=10,C=10+12-9=13
F(x)=4x-x³/3+13