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July 2022
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найти площадь фигуры
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Gerren
S=∫t1,t2(x(t)'*y(t))dt
x(t)'=10-10cos(t)
S=∫0,20pi(10-(1-cos(t)*(10-10cot(t))=∫0,20pi(1-cos(t))^2dt=∫0,20pi(3x/2-2sinx+1/4*sin2x=30pi
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Answers & Comments
x(t)'=10-10cos(t)
S=∫0,20pi(10-(1-cos(t)*(10-10cot(t))=∫0,20pi(1-cos(t))^2dt=∫0,20pi(3x/2-2sinx+1/4*sin2x=30pi