1)dy=d(2x^3 + 5x^2) = (6x^2+10x)dx
Δy = (6x^2+10x)Δх = 16*0,1 = 1,6
2)dy=d(x^2 + 5x)=(2x +5)dx
Δy = (2x +5)Δх = 9*0,001 = 0,009
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1)dy=d(2x^3 + 5x^2) = (6x^2+10x)dx
Δy = (6x^2+10x)Δх = 16*0,1 = 1,6
2)dy=d(x^2 + 5x)=(2x +5)dx
Δy = (2x +5)Δх = 9*0,001 = 0,009