Найти производную функции 1) y= e^-2x 2) y= 5sin7x

yanayarova00 @yanayarova00

August 2022 1 24 Report

Найти производную функции
1) y= e^-2x
2) y= 5sin7x - 7x2 + 7

Answers & Comments

NNNLLL54

Verified answer

$1)\; \; y=e^{-2x}\\\\y'=e^{-2x}\cdot (-2x)'=-2\cdot e^{-2x}\\\\2)\; \; y=5\cdot sin7x-7x^2+7\\\\y'=5\cdot cos7x\cdot \underbrace {(7x)'}_{7}-7\cdot 2x=35\cdot cos7x-14x$

16 votes Thanks 24

Answers & Comments

Verified answer

Helpful Links

Helpful Social