Найти производную функции 1) y= e^-2x 2) y= 5sin7x

yanayarova00 @yanayarova00

August 2022 1 15 Report

Найти производную функции
1) y= e^-2x
2) y= 5sin7x - 7x2 + 7

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NNNLLL54

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$1)\; \; y=e^{-2x}\\\\y'=e^{-2x}\cdot (-2x)'=-2\cdot e^{-2x}\\\\2)\; \; y=5\cdot sin7x-7x^2+7\\\\y'=5\cdot cos7x\cdot \underbrace {(7x)'}_{7}-7\cdot 2x=35\cdot cos7x-14x$

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yanayarova00 August 2022 | 0 Ответы

pomogite pozhalujstafb7b1998546a3e0107e55f7fc0608391 32376

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yanayarova00 August 2022 | 0 Ответы

a a98739cdc60d1ba3ab57461f1b2c78f6c 67844

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