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yuruyu33
@yuruyu33
June 2022
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Найти производную функции:
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Tanda80
Первый способ. Используем правило вычисления производной произведения.
y'=t'(√t+1)+t(√t+1)'
y'=√t+1+t*1/(2√t)
y'=√t+1+√t/2
y'=3√t/2+1
Второй способ. Преобразуем данную функцию: у=t(√t+1), y=t*√t+t, y=t^(3/2)+t.
y'=(t^(3/2))'+t'
y'=3/2*t^(1/2)+1
y'=3√t/2+1
2 votes
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Answers & Comments
y'=t'(√t+1)+t(√t+1)'
y'=√t+1+t*1/(2√t)
y'=√t+1+√t/2
y'=3√t/2+1
Второй способ. Преобразуем данную функцию: у=t(√t+1), y=t*√t+t, y=t^(3/2)+t.
y'=(t^(3/2))'+t'
y'=3/2*t^(1/2)+1
y'=3√t/2+1