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umeda1627
@umeda1627
August 2022
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найти производную y=sin^2x cosx
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mikael2
Verified answer
Не вовсе ясно - sin²x?
пусть так, y=sin²x*cosx y'=(uv)'=u'v+v'u u=sin²x, v=cosx
y'=2sinx*(sinx)'+(cosx)'sin²x=2sinx*cosx-sinx*sin²x=sin2x-sin³x
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Answers & Comments
Verified answer
Не вовсе ясно - sin²x?пусть так, y=sin²x*cosx y'=(uv)'=u'v+v'u u=sin²x, v=cosx
y'=2sinx*(sinx)'+(cosx)'sin²x=2sinx*cosx-sinx*sin²x=sin2x-sin³x