y`=[(x²+1)`(x²+x+1)-(x²+x+1)`(x²+1)]/(x²+x+1)²
=[2x(x²+x+1)-2x(x²+1)]/(x²+x+1)²=(2x³+2x²+2x-2x³-2x-x²-1)/(x²+x+1)²=
=(x²-1)/(x²+x+1)²
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y`=[(x²+1)`(x²+x+1)-(x²+x+1)`(x²+1)]/(x²+x+1)²
=[2x(x²+x+1)-2x(x²+1)]/(x²+x+1)²=(2x³+2x²+2x-2x³-2x-x²-1)/(x²+x+1)²=
=(x²-1)/(x²+x+1)²
=[2x(x²+x+1)-2x(x²+1)]/(x²+x+1)²=(2x³+2x²+2x-2x³-2x-x²-1)/(x²+x+1)²=
=(x²-1)/(x²+x+1)²