2Cr(+3) + 16 oh(-) - 6e = 2Cro4(2-) +8 h2o | 1 вль
H2o2(0) + h2o + 2e = h2o(0) +2oh(-) | 3 окль
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2Cr(+3) + 16 oh(-) - 6e = 2Cro4(2-) +8 h2o | 1 вль
H2o2(0) + h2o + 2e = h2o(0) +2oh(-) | 3 окль