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NightWolf123
@NightWolf123
April 2022
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Напишите электролиз раствора иодида цинка.
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prevedd91
ZnI2+2H2O=Zn(OH)2+H2↑+I2↑
ZnI2 = Zn2+ + I–,
H2O = Н+ + ОН–;
катод (–) (Zn2+; Н+): H+ + 1е = H0, 2H0 = H2
(2H2O + 2е = H2 + 2OH–),
анод (+) (I–; OН–): I– – 2е = I0, 2I0 = I2;
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Answers & Comments
ZnI2 = Zn2+ + I–,
H2O = Н+ + ОН–;
катод (–) (Zn2+; Н+): H+ + 1е = H0, 2H0 = H2 (2H2O + 2е = H2 + 2OH–),
анод (+) (I–; OН–): I– – 2е = I0, 2I0 = I2;