saintegg #include <iostream>#include <math.h>
int main(){ int a, b, c; double x1, x2, d; std::cin>>a>>b>>c; if ((b*b-4*a*c)>=0)  { d = sqrt(b*b-4*a*c); std::cout<<"Your equation:\n"<<a<<"*x*x + ("<<b<<") + ("<<c<<") = 0\n\n"; x1 = (-b+d)/(2*a); x2 = (-b-d)/(2*a); std::cout<<"x1:  "<<x1<<"\nx2:  "<<x2; } else std::cout<<"No solution\n"; return 0;
}

eugene7870 Мой вариант решения :)
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