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Alex1709228
@Alex1709228
July 2022
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Не выполняя построения найдите координаты точек пересечения параболы y=x^2-6x+9 и прямой x-y=1
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ученик1484
y=-1+x
1+x=x^2-6x+9
x^2-6x+9+1-x=0
x^2-7x+10=0
D=49-40=9
x=(7-3)÷2=2
x=(7+3)÷2=5
y=1+2=3
y=1+5=6
(2;3) и (5;6)
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Answers & Comments
y=-1+x
1+x=x^2-6x+9
x^2-6x+9+1-x=0
x^2-7x+10=0
D=49-40=9
x=(7-3)÷2=2
x=(7+3)÷2=5
y=1+2=3
y=1+5=6
(2;3) и (5;6)