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Alex1709228
@Alex1709228
July 2022
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Не выполняя построения найдите координаты точек пересечения параболы y=x^2-6x+9 и прямой x-y=1
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blentsov
y=x^2+4
x+y=6
y=x^2+4
у= 6-х
х^2+4 = 6 - x
x^2 + x+4 - 6 = 0
x^2+x - 2 = 0
D= 1 +8= 9
x₁= -1+3/2 = 1
х₂= -1-3/2 =- 2
у₁= 5
у₂= 8
Ответ: (1;5) и (-2;8).
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Answers & Comments
x+y=6
y=x^2+4
у= 6-х
х^2+4 = 6 - x
x^2 + x+4 - 6 = 0
x^2+x - 2 = 0
D= 1 +8= 9
x₁= -1+3/2 = 1
х₂= -1-3/2 =- 2
у₁= 5
у₂= 8
Ответ: (1;5) и (-2;8).