[tex]N(NH3) = 12,04*10^{23}\\\\Na = 6,02*10^{23}\\\\n = \frac{N}{Na} \\\\n(NH3) = \frac{12,04*10^{23}}{6,02*10^{23}} = 2mol[/tex]
m = M × n
M(NH3) = 17 г/моль
m(NH3) = 17 × 2 = 34 г
V = Vm × n
Vm = 22,4 л
V(NH3) = 22,4 × 2 = 44,8 л
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[tex]N(NH3) = 12,04*10^{23}\\\\Na = 6,02*10^{23}\\\\n = \frac{N}{Na} \\\\n(NH3) = \frac{12,04*10^{23}}{6,02*10^{23}} = 2mol[/tex]
m = M × n
M(NH3) = 17 г/моль
m(NH3) = 17 × 2 = 34 г
V = Vm × n
Vm = 22,4 л
V(NH3) = 22,4 × 2 = 44,8 л