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Ninsi18
@Ninsi18
July 2022
1
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Номер 1 (б), номер 2, номер 4 (а). На левой странице
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sedinalana
1б
x∈(-∞;-3) U (-3;3) U (3;∞)
2
(x+5)/4+(x-6)/2=(x+5+2x-12)/4=(3x-7)/4
1/(x-3)+1/(x+3)=(x+3+x-3)/(x²-9)=2x/(x²-9)
(x-4)/3(x+2)+(3x-1)/x(x+2)=(x²-4x+9x-3)/6x(x+2)=(x²+5x-3)/6x(x+2)
4a
x=-1
(1-5-3)/[-6(-1+2)]=-7/(-6)=7/6
1 votes
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Ninsi18
А можете сделать в номере один и пункт в?
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Answers & Comments
x∈(-∞;-3) U (-3;3) U (3;∞)
2
(x+5)/4+(x-6)/2=(x+5+2x-12)/4=(3x-7)/4
1/(x-3)+1/(x+3)=(x+3+x-3)/(x²-9)=2x/(x²-9)
(x-4)/3(x+2)+(3x-1)/x(x+2)=(x²-4x+9x-3)/6x(x+2)=(x²+5x-3)/6x(x+2)
4a
x=-1
(1-5-3)/[-6(-1+2)]=-7/(-6)=7/6