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Dakileno
@Dakileno
July 2022
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Номер 1276 а, в и 1277 полностью
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1276 (а, в
)
φ (х) = 2х - 5
а) φ (х + 3) = φ (3х)
2(х + 3) - 5 = 2* 3х - 5
2х + 6 - 5 = 6х - 5
2х - 6х = 5 - 5
- 4х = 0
х = 0
в) 2 φ (х) = - φ (х - 1)
2(2х - 5) = - (2(х - 1) - 5)
4х - 10 = - (2х - 2 - 5)
4х - 10 = - (2х - 7)
4х - 10 = - 2х + 7
4х + 2х = 10 + 7
6х = 17
х = 17/6
х = 2 5/6
1277
а) D(f) = [ - 6 ; 5 ]
б) f(-5) = -5 + 4 = -1
f(1) = - 1 + 2 = 1
f(4) = 4
в) Е(f) = [ - 2 ; 5 ]
г) f(х) = 0 при х = -4
f(х) = 2 при х = -2 или х = 2
f(х) = 3 при х = - 1 или х = 3
f(х) = 4 при х = 4
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Answers & Comments
φ (х) = 2х - 5
а) φ (х + 3) = φ (3х)
2(х + 3) - 5 = 2* 3х - 5
2х + 6 - 5 = 6х - 5
2х - 6х = 5 - 5
- 4х = 0
х = 0
в) 2 φ (х) = - φ (х - 1)
2(2х - 5) = - (2(х - 1) - 5)
4х - 10 = - (2х - 2 - 5)
4х - 10 = - (2х - 7)
4х - 10 = - 2х + 7
4х + 2х = 10 + 7
6х = 17
х = 17/6
х = 2 5/6
1277
а) D(f) = [ - 6 ; 5 ]
б) f(-5) = -5 + 4 = -1
f(1) = - 1 + 2 = 1
f(4) = 4
в) Е(f) = [ - 2 ; 5 ]
г) f(х) = 0 при х = -4
f(х) = 2 при х = -2 или х = 2
f(х) = 3 при х = - 1 или х = 3
f(х) = 4 при х = 4