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ghostkote
@ghostkote
August 2021
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номер 3 помогите пожалуйста умоляю, с решением
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Verified answer
Ctg (α/2) = 1/2 ⇒ tg (α/2) = 2
tg (α) = 2 tg (α/2)/(1-tg² (α/2))= 4/(1-2²)= -4/3
ctg (α) = -3/4
sinα= 2tg (α)/(1+tg²α)= 4/(1+4)=4/5
cosα= (1-tg² (α))/(1+tg²α)=(1- 4)/(1+4)=-3/5
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Answers & Comments
Verified answer
Ctg (α/2) = 1/2 ⇒ tg (α/2) = 2tg (α) = 2 tg (α/2)/(1-tg² (α/2))= 4/(1-2²)= -4/3
ctg (α) = -3/4
sinα= 2tg (α)/(1+tg²α)= 4/(1+4)=4/5
cosα= (1-tg² (α))/(1+tg²α)=(1- 4)/(1+4)=-3/5