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ghostkote
@ghostkote
August 2021
1
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тема 2, любой вариант 20 баллов
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svetazuna
Вариант 1.
1.
[4^(1,5) * 8^(4)] / [16^(2,5) * 64^(0,5)] =
= [2^(2*1,5) * 2^(3*4)] / (2^(4*2,5) * 2^(6*0,5)] =
= [2^(3) * 2^(12)] / (2^(10) * 2^(3)] =
= [2^(3+12)] / (2^(10+3)] =
= 2^(15) / 2^(13) =
= 2^(15-13) =
= 2²
= 4.
2.
(64-8c³)/(16-4c²) * (4+2c) =
= [8*(8-c³)]/[4*(4-c²)] * (4+2c) =
= [8*(2-c)(4+2c+c²)]/[4*(2-c)(2+c)] * (2+c)*2 =
= 8/2 * (4+2c+c²) =
4*(4+2c+c²).
2 votes
Thanks 1
ghostkote
для чего квадратные скобки?
svetazuna
чтобы было понятнее, я отделила числитель и знаменатель квадратными скобками, просто когда пишешь большие примеры в строчку, все сливается в кучу. а вообще они не нужны
ghostkote
спасибо, я понял
svetazuna
:))
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Answers & Comments
1.
[4^(1,5) * 8^(4)] / [16^(2,5) * 64^(0,5)] =
= [2^(2*1,5) * 2^(3*4)] / (2^(4*2,5) * 2^(6*0,5)] =
= [2^(3) * 2^(12)] / (2^(10) * 2^(3)] =
= [2^(3+12)] / (2^(10+3)] =
= 2^(15) / 2^(13) =
= 2^(15-13) =
= 2² = 4.
2.
(64-8c³)/(16-4c²) * (4+2c) =
= [8*(8-c³)]/[4*(4-c²)] * (4+2c) =
= [8*(2-c)(4+2c+c²)]/[4*(2-c)(2+c)] * (2+c)*2 =
= 8/2 * (4+2c+c²) = 4*(4+2c+c²).