Номер 7 решите пожалуйста срочно. Created by ChetyshXX. algebra-ru

Номер 7 решите пожалуйста срочно...

JustDiana99 (-1^3-2*(-1)+1/1^2+4)*(1^4+16/-1-1)=(-1+2+1/5)*(1-16/-2)=2/5*15/2=3

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GreatFilter $\frac{a^{3}-2a+1}{b^{2}+4} * \frac{b^{4}-16}{a-1} = \frac{a^{3}-2a+1}{b^{2}+4} * \frac{(b^{2}+4)(b^{2}-4)}{a-1} = \frac{a^{3}-2a+1}{1} * \frac{b^{2}-4}{a-1} \\ a=-1 \\ b=1 \\ \\ \frac{(-1)^{3}-2*(-1)+1}{1} * \frac{1^{2}-4}{-1-1}= \frac{-1+2+1}{1} * \frac{1-4}{-2}=\frac{2}{1} * \frac{-3}{-2}= \frac{-3}{-1} =3$

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1 a h3x2 x 1 b 16 4aa3 a4 2 a pk 4pk4 b a b5ab5 v x

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