Нужна помощь! Очень срочно!!! решение 4,5,6. Created by shpont. matematika-ru

4а)(1/2)^6x≤(1/2)^3/26x≥3/2 (основание меньше 1,знак меняется)x≥1/4x∈[0,25;∞)б)ОДЗ(x-5)/(x-4)>0x=4 U x=5x∈(-∞;4) U (5;∞)(x-5)/(x-4)<2(x-5)/(x-4)-2<0(x-5-2x+8)/(x-4)<0(3-x)/(x-4)<0(x-3)(x-4)>0x=3 x=4x<3 U x>4x∈(-∞;3) U (5;∞)58x²-2x-1=0D=4+32=36x1=(2-6)/16=-1/4x2=(2+6)/16=1/2x=0 _ + _ +-------------[-1/4]------------(0)--------[1/2]--------------x∈(-∞;-1/4] U (0;1/2]6ОДЗ{x-4≥0⇒x≥4{x+24≥0⇒x≥-24x∈[4;∞)возведем в квадратx-4+2√(x²+20x-96)+x+24=1962√(x²+20x-96)=176-2x√(x²+20x-96)=88-xвозведем в квадратx²+20x-96=7744-176x+x²196x=7840x=7840:196x=40 Новые вопросы в МатематикаIMG_20220806_010323.jpgIMG_20220806_010323.jpg11) Автомобиль проехал 5/8 пути.Если он проедет 60 км, то 1/4 пути останется непройденным.Найдите длину этого пути? СРОЧНОПривет всем! Очень нужна помощь, заранее благодарен.. Как доказать, что из левого получается правое?tgx+tgy=4cosx·cosy=1/5найти:tg(x+y)Побудуйте графік залежності змінної у від змінної х, яку задано формулою у = -2х. С объяснением пожалуйстаВ треугольнике MNK MN=10cм, NK=20см, угол N равен 98 градусовНадо найти:1. длину стороны MK2. углы M и K3. площадь треугольника MNK4. периметр т…р-ка MNK5. длину высоты NS12. Сторони паралелограма дорівнюють 12 см і 9 см, а сумадвох його висот, проведених з однієї вершини, - 7 см. Знай-діть площу паралелограма.ноДжинсы стоили 500 рублей,потом цену снизили на20% на сколько % надоповысить, чтобы джинсыснова сталистоить 500р?С нормальным объяснением пожалуйстаПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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\u0410\u0432\u0442\u043e\u043c\u043e\u0431\u0438\u043b\u044c \u043f\u0440\u043e\u0435\u0445\u0430\u043b 5\/8 \u043f\u0443\u0442\u0438.\u0415\u0441\u043b\u0438 \u043e\u043d \u043f\u0440\u043e\u0435\u0434\u0435\u0442 60 \u043a\u043c, \u0442\u043e 1\/4 \u043f\u0443\u0442\u0438 \u043e\u0441\u0442\u0430\u043d\u0435\u0442\u0441\u044f \u043d\u0435\u043f\u0440\u043e\u0439\u0434\u0435\u043d\u043d\u044b\u043c.\u041d\u0430\u0439\u0434\u0438\u0442\u0435 \u0434\u043b\u0438\u043d\u0443 \u044d\u0442\u043e\u0433\u043e \u043f\u0443\u0442\u0438? \u0421\u0420\u041e\u0427\u041d\u041e\u200b"},{"id":49787184,"content":"\u041f\u0440\u0438\u0432\u0435\u0442 \u0432\u0441\u0435\u043c! \u041e\u0447\u0435\u043d\u044c \u043d\u0443\u0436\u043d\u0430 \u043f\u043e\u043c\u043e\u0449\u044c, \u0437\u0430\u0440\u0430\u043d\u0435\u0435 \u0431\u043b\u0430\u0433\u043e\u0434\u0430\u0440\u0435\u043d.. \u041a\u0430\u043a \u0434\u043e\u043a\u0430\u0437\u0430\u0442\u044c, \u0447\u0442\u043e \u0438\u0437 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98 \u0433\u0440\u0430\u0434\u0443\u0441\u043e\u0432\n\u041d\u0430\u0434\u043e \u043d\u0430\u0439\u0442\u0438: \n1. \u0434\u043b\u0438\u043d\u0443 \u0441\u0442\u043e\u0440\u043e\u043d\u044b MK\n2. \u0443\u0433\u043b\u044b M \u0438 K\n3. \u043f\u043b\u043e\u0449\u0430\u0434\u044c \u0442\u0440\u0435\u0443\u0433\u043e\u043b\u044c\u043d\u0438\u043a\u0430 MNK\n4. \u043f\u0435\u0440\u0438\u043c\u0435\u0442\u0440 \u0442\u0440-\u043a\u0430 MNK\n5. \u0434\u043b\u0438\u043d\u0443 \u0432\u044b\u0441\u043e\u0442\u044b NS"},{"id":49787017,"content":"12. \u0421\u0442\u043e\u0440\u043e\u043d\u0438 \u043f\u0430\u0440\u0430\u043b\u0435\u043b\u043e\u0433\u0440\u0430\u043c\u0430 \u0434\u043e\u0440\u0456\u0432\u043d\u044e\u044e\u0442\u044c 12 \u0441\u043c \u0456 9 \u0441\u043c, \u0430 \u0441\u0443\u043c\u0430\n\u0434\u0432\u043e\u0445 \u0439\u043e\u0433\u043e \u0432\u0438\u0441\u043e\u0442, \u043f\u0440\u043e\u0432\u0435\u0434\u0435\u043d\u0438\u0445 \u0437 \u043e\u0434\u043d\u0456\u0454\u0457 \u0432\u0435\u0440\u0448\u0438\u043d\u0438, - 7 \u0441\u043c. \u0417\u043d\u0430\u0439-\n\u0434\u0456\u0442\u044c \u043f\u043b\u043e\u0449\u0443 \u043f\u0430\u0440\u0430\u043b\u0435\u043b\u043e\u0433\u0440\u0430\u043c\u0430."},{"id":49786965,"content":"\u043d\u043e\n\u0414\u0436\u0438\u043d\u0441\u044b \u0441\u0442\u043e\u0438\u043b\u0438 500 \u0440\u0443\u0431\u043b\u0435\u0439,\n\u043f\u043e\u0442\u043e\u043c \u0446\u0435\u043d\u0443 \u0441\u043d\u0438\u0437\u0438\u043b\u0438 \u043d\u0430\n20% \u043d\u0430 \u0441\u043a\u043e\u043b\u044c\u043a\u043e % \u043d\u0430\u0434\u043e\n\u043f\u043e\u0432\u044b\u0441\u0438\u0442\u044c, \u0447\u0442\u043e\u0431\u044b \u0434\u0436\u0438\u043d\u0441\u044b\n\u0441\u043d\u043e\u0432\u0430 \u0441\u0442\u0430\u043b\u0438\n\u0441\u0442\u043e\u0438\u0442\u044c 500\u0440?"},{"id":49786904,"content":"\u0421 \u043d\u043e\u0440\u043c\u0430\u043b\u044c\u043d\u044b\u043c \u043e\u0431\u044a\u044f\u0441\u043d\u0435\u043d\u0438\u0435\u043c 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Нужна помощь! Очень срочно!!! решение 4,5,6...

shpont @shpont

August 2022 1 14 Report

Нужна помощь! Очень срочно!!! решение 4,5,6

Answers & Comments

sedinalana

Verified answer

4
а)(1/2)^6x≤(1/2)^3/2
6x≥3/2 (основание меньше 1,знак меняется)
x≥1/4
x∈[0,25;∞)
б)ОДЗ
(x-5)/(x-4)>0
x=4 U x=5
x∈(-∞;4) U (5;∞)
(x-5)/(x-4)<2
(x-5)/(x-4)-2<0
(x-5-2x+8)/(x-4)<0
(3-x)/(x-4)<0
(x-3)(x-4)>0
x=3 x=4
x<3 U x>4
x∈(-∞;3) U (5;∞)
5
8x²-2x-1=0
D=4+32=36
x1=(2-6)/16=-1/4
x2=(2+6)/16=1/2
x=0
_ + _ +
-------------[-1/4]------------(0)--------[1/2]--------------
x∈(-∞;-1/4] U (0;1/2]
6
ОДЗ
{x-4≥0⇒x≥4
{x+24≥0⇒x≥-24
x∈[4;∞)
возведем в квадрат
x-4+2√(x²+20x-96)+x+24=196
2√(x²+20x-96)=176-2x
√(x²+20x-96)=88-x
возведем в квадрат
x²+20x-96=7744-176x+x²
196x=7840
x=7840:196
x=40