v1248
I7=110/20=5.5 A R23=1/(1/4+1/12)=3 Ом R456=1/(1/6+1/3+1/8)=1.6 Ом R123456=6.4+3+1.6=11 Ом I1=110/11=10 A U23=10·3=30 В I2=30/4=7.5 A I3=30/12=2.5 A U456=10·1.6=16 В I4=16/6=2.7 A I5=16/3=5.3 A I6= 16/8 = 2 A Результат I1=10 A I2=7.5 A I3=2.5 A I4=2.7 A I5=5.3 A I6 = 2 A I7=5.5 A
Answers & Comments
R23=1/(1/4+1/12)=3 Ом
R456=1/(1/6+1/3+1/8)=1.6 Ом
R123456=6.4+3+1.6=11 Ом
I1=110/11=10 A
U23=10·3=30 В
I2=30/4=7.5 A
I3=30/12=2.5 A
U456=10·1.6=16 В
I4=16/6=2.7 A
I5=16/3=5.3 A
I6= 16/8 = 2 A
Результат
I1=10 A
I2=7.5 A
I3=2.5 A
I4=2.7 A
I5=5.3 A
I6 = 2 A
I7=5.5 A