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SammyRussophile
@SammyRussophile
August 2022
2
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Нужно решение этой фигни, срочно ёу.
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Answers & Comments
iriska124
1)4^(x²+x)=1
4^(x²+x)=4^(0)
x²+x=0
x*(x+1)=0
х=0
или
х=-1
2)2^(x)=32
2^(x)=2^(5)
x=5
1 votes
Thanks 0
Nocomment13
2^x = 32
2^(x) = 2^5
2x =5
x = 2.5
0 votes
Thanks 0
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Answers & Comments
4^(x²+x)=4^(0)
x²+x=0
x*(x+1)=0
х=0
или
х=-1
2)2^(x)=32
2^(x)=2^(5)
x=5
2^(x) = 2^5
2x =5
x = 2.5