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vohmyakov2009
@vohmyakov2009
July 2022
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Нужно решить и расписать!
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aleksobuhov350
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По закону Ома I=E/R; R1=E/I; R1=60/1.2=50 Ом;
I=1.2 А; I1=60/(50+250)=0.2 А;
E1-E=14 Дж; LI₁²/2-LI²/2=14 Дж
L(I₁²-I²)=28; L=28/(I₁²-I²); L=28/(1.2²-0.2²)=20 Гн
Ответ:
L=20 Гн
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Answers & Comments
Verified answer
По закону Ома I=E/R; R1=E/I; R1=60/1.2=50 Ом;I=1.2 А; I1=60/(50+250)=0.2 А;
E1-E=14 Дж; LI₁²/2-LI²/2=14 Дж
L(I₁²-I²)=28; L=28/(I₁²-I²); L=28/(1.2²-0.2²)=20 Гн
Ответ: L=20 Гн