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kindness5
@kindness5
July 2022
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Нужно решить задачу 3KOH+H3PO4=K3PO4+3H2O H3PO4(100 г ) , 3KOH (x г)
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Alexei78
Дано
m(H3PO4)=100 g
------------------
m(KOH)-?
X 100
3KOH+H3PO4-->K3PO4+3H2O M(KOH)=56 g/mol , M(H3PO4)=98 g/mol
3*56 98
X / 168 = 100 / 98
X=171.43 g
ответ 171.43 г
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Answers & Comments
m(H3PO4)=100 g
------------------
m(KOH)-?
X 100
3KOH+H3PO4-->K3PO4+3H2O M(KOH)=56 g/mol , M(H3PO4)=98 g/mol
3*56 98
X / 168 = 100 / 98
X=171.43 g
ответ 171.43 г