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nastya1mailcon
@nastya1mailcon
July 2022
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объясните пожалуйста, как решаются эти две задачи
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xxxeol
РЕШЕНИЕ
10.
∠DOC = 90/2 = 45° - биссектриса
∠COE = 90 - 30 = 60° - разность
∠DOE = 45+60 = 105° - сумма - ОТВЕТ
13
∠1 + ∠2 = ∠3 = 130°
∠2 = 130 /2 = 65°
∠D = 180 - 130 = 50°
∠C = 180 - ∠2 - ∠D = 180 - 65 - 50 = 65° - ОТВЕТ
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Answers & Comments
10.
∠DOC = 90/2 = 45° - биссектриса
∠COE = 90 - 30 = 60° - разность
∠DOE = 45+60 = 105° - сумма - ОТВЕТ
13
∠1 + ∠2 = ∠3 = 130°
∠2 = 130 /2 = 65°
∠D = 180 - 130 = 50°
∠C = 180 - ∠2 - ∠D = 180 - 65 - 50 = 65° - ОТВЕТ