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Kotena1996
@Kotena1996
November 2021
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очень нужно решить задания,помогите:)
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dnepr1
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15) 0.08^(1/7)*5^(3/7)*10^(6/7) = (8 / 100^(1/7)*5^(3/7)*2^(6/7)*5^(6/7) =
= (2^(3/7) / (2^(2/7)*5^(2/7))*5^(3/7)*2^(6/7)*5^(6/7) =2*5 = 10.
16) 9*125^(1/4)*125^(1/12) = 9*5^(3/4)*5^(3/12) = 9*5 = 45.
17) 64^(1/6)*64^(1/3) = 2^(6/6)*2^(6/3) = 2^3 = 8.
18) (5^(1/20)*5^(1/5)) / 5^(1/4) = 5^(1/20+1/5-1/4) = 5^0=1.
19) (6^(1/3)*12^(1/3)) / 9^(1/3) = (2*3^(2/3)) / 3^(2/3) = 2.
20) (2^5)^6 / 2^32 = 2^(30-32) = 2^(-2) = 1/4.
21) (36^6)^3 / (6^4)^8 = 6^36*6^(-32) = 6^(36-32) = 6^4 = 1296.
22) (2^(1/2)*2^(1/3)) / 2^(1/3) = 2^(1/2+1/3-1/3) = 2^(1/2) = √2.
23) ((5^(4/7)*11^(2/3))^21) / 55^12 = ((5^84*11^(42/3)) / (5^12*11^12) =
= 11² = 121.
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Answers & Comments
Verified answer
15) 0.08^(1/7)*5^(3/7)*10^(6/7) = (8 / 100^(1/7)*5^(3/7)*2^(6/7)*5^(6/7) == (2^(3/7) / (2^(2/7)*5^(2/7))*5^(3/7)*2^(6/7)*5^(6/7) =2*5 = 10.
16) 9*125^(1/4)*125^(1/12) = 9*5^(3/4)*5^(3/12) = 9*5 = 45.
17) 64^(1/6)*64^(1/3) = 2^(6/6)*2^(6/3) = 2^3 = 8.
18) (5^(1/20)*5^(1/5)) / 5^(1/4) = 5^(1/20+1/5-1/4) = 5^0=1.
19) (6^(1/3)*12^(1/3)) / 9^(1/3) = (2*3^(2/3)) / 3^(2/3) = 2.
20) (2^5)^6 / 2^32 = 2^(30-32) = 2^(-2) = 1/4.
21) (36^6)^3 / (6^4)^8 = 6^36*6^(-32) = 6^(36-32) = 6^4 = 1296.
22) (2^(1/2)*2^(1/3)) / 2^(1/3) = 2^(1/2+1/3-1/3) = 2^(1/2) = √2.
23) ((5^(4/7)*11^(2/3))^21) / 55^12 = ((5^84*11^(42/3)) / (5^12*11^12) =
= 11² = 121.