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Kotena1996
@Kotena1996
July 2022
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1/sin^2x-1-ctgx=0 решите плисс
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mmb1
Verified answer
1/sin²x-1-ctgx=0
1-1/sin²x=ctg²x
-ctg²x-ctgx=0
ctgx(ctgx+1)=0
ctgx=0
x=π/2+πN
ctgx=-1
x=-π/4+πN
6 votes
Thanks 12
Kotena1996
Так ведь котангенса 0 не существует?
mmb1
Да что ВЫ ???? И когда это произошло ????
Kotena1996
В тригонометрической таблице его нет...Да и как он будет,на 0 нельзя делить
mmb1
ctgx=0 x=pi/2
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Answers & Comments
Verified answer
1/sin²x-1-ctgx=01-1/sin²x=ctg²x
-ctg²x-ctgx=0
ctgx(ctgx+1)=0
ctgx=0
x=π/2+πN
ctgx=-1
x=-π/4+πN