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oksanka1060
@oksanka1060
September 2021
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одновалентний метал масою 9,2г при взаємодії з водою витискає 4,48л газу.Який це метал?
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alishady99
2Me + 2H2O = 2MeOH + H2
n(H2) = 4.48л/22.4л =0.2моль
n(Me) : n(H2) = 2 : 1
n(Me) = 0.2 ×2 = 0.4
M(Me) = 9.2 / 0.4 = 23г/моль (Na)
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Answers & Comments
n(H2) = 4.48л/22.4л =0.2моль
n(Me) : n(H2) = 2 : 1
n(Me) = 0.2 ×2 = 0.4
M(Me) = 9.2 / 0.4 = 23г/моль (Na)