Ответ:
R34=40*10/(40+10)= 8 Ом, Ro=R1+R2+R34+R5=
8+6+8+4= 26 Om, I=U/Ro=52/26=2A
Е=U+Ir= 52+2*1= 54 B
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Ответ:
R34=40*10/(40+10)= 8 Ом, Ro=R1+R2+R34+R5=
8+6+8+4= 26 Om, I=U/Ro=52/26=2A
Е=U+Ir= 52+2*1= 54 B