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Эльзик1
@Эльзик1
August 2022
1
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Определите формулу вещества по массовым долям элементов, если в состав веществ входит:
6% водорода
94% серы
его Mr=34
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alona97
W(E)=(Ar(E)*n)/Mr
n(H)=W*Mr/Ar=0,06*34/1=2
n(S)=W*Mr/Ar=0,94*34/32=1
H2S
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Answers & Comments
n(H)=W*Mr/Ar=0,06*34/1=2
n(S)=W*Mr/Ar=0,94*34/32=1
H2S