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vladpaskevits
@vladpaskevits
September 2021
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Определите содержание олова в сплаве, полученном при сплавлении 300г 20%-го сплава и 200г 40%-го сплава.
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Костяша
Verified answer
0,2*300=60
0,4*200=80
60+80=140г
300+200=500 г
100*140/500=28%
2 votes
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Answers & Comments
Verified answer
0,2*300=600,4*200=80
60+80=140г
300+200=500 г
100*140/500=28%