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himaman
@himaman
August 2021
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Период полураспада радиоактивного фосфора равен 3 мин. Чему равна постоянная распада этого элемента?
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Verified answer
T = 3 мин = 180 с
λ = ln 2 / T = 0,693 / 180 ≈ 0,0039 c⁻¹
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Verified answer
T = 3 мин = 180 сλ = ln 2 / T = 0,693 / 180 ≈ 0,0039 c⁻¹