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LionShilov
@LionShilov
August 2022
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По физике решить.........
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MashaPutnaj
Verified answer
m=0,4 кг
t1=20 C
t2=100 C
Q1= c*m*(t2-t1)= 4200*0,4*80=134400 Дж=134 кДж
Q2= L*m= 2300000*0,4=920000 Дж=920кДж
Найдем все тепло на нагревание и испарение Q=Q1+Q2=1054 кДж
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Answers & Comments
Verified answer
m=0,4 кг
t1=20 C
t2=100 C
Q1= c*m*(t2-t1)= 4200*0,4*80=134400 Дж=134 кДж
Q2= L*m= 2300000*0,4=920000 Дж=920кДж
Найдем все тепло на нагревание и испарение Q=Q1+Q2=1054 кДж