<B=180°-50°-70°=60°
найдем стороны по теореме синусов
sina/BC=sinb/AC=sinc/AB
BC=sina*AB/sinc=0.766*6/0.9397=4.89
AC=AB*sinb/sinc=6*0.866/0.9397=5.53
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<B=180°-50°-70°=60°
найдем стороны по теореме синусов
sina/BC=sinb/AC=sinc/AB
BC=sina*AB/sinc=0.766*6/0.9397=4.89
AC=AB*sinb/sinc=6*0.866/0.9397=5.53