#7
x + y - x³ - y³ = (x + y) + (- x³ - y³) = (x + y) - (x³ + y³) = (x + y) - (x + y)(x² - xy + y²) = (x + y)(1 - (x² - xy + y²)) = (x + y)(1 - x² + xy - y²)
x+y-x³-y³ = x+y-(x³+y³) = x+y-(x+y)(x²-xy+y²) = 1(x+y)-(x²-xy+y²)(x+y) = (x+y)(1-x²+xy-y²)
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
#7
x + y - x³ - y³ = (x + y) + (- x³ - y³) = (x + y) - (x³ + y³) = (x + y) - (x + y)(x² - xy + y²) = (x + y)(1 - (x² - xy + y²)) = (x + y)(1 - x² + xy - y²)
x+y-x³-y³ = x+y-(x³+y³) = x+y-(x+y)(x²-xy+y²) = 1(x+y)-(x²-xy+y²)(x+y) = (x+y)(1-x²+xy-y²)