Ответ:
1)
2)x³-x=0
x(x²-1)=0
x=0 или x²-1=0
x²=1
x=1
3)
Пошаговое объяснение:
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
1)
2)x³-x=0
x(x²-1)=0
x=0 или x²-1=0
x²=1
x=1
3)
Ответ:
Пошаговое объяснение: