(4a−17b+23c)−(−17a+23b−17c)=4a+17a−17b-23b+23c+17c=21a−40b+40c
Ответ:2)21a−40b+40c
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(4a−17b+23c)−(−17a+23b−17c)=4a+17a−17b-23b+23c+17c=21a−40b+40c
Ответ:2)21a−40b+40c