Получите 2,2-диметилпропановую кислоту из бромистого трет-бутила.
CH3 CH3
| |
CH3 - C - CH3 + 2Na + CH3Br ----- > CH3 - C - CH3 + 2NaCl
Br CH3
CH3 - C - CH3 +Cl2 -------> CH3 - C - CH2Cl + HCl
(2,2-диметил3-хлорпропан)
CH3 - C - CH2Cl +NaOH -------> CH3 - C - CH2OH + NaCl
(2,2-диметилпропанол-1)
| Kt,t |
CH3 - C - CH2OH +O2 -------> CH3 - C - COOH + H2O
(2.2-диметилпропановая кислота)
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Verified answer
CH3 CH3
| |
CH3 - C - CH3 + 2Na + CH3Br ----- > CH3 - C - CH3 + 2NaCl
| |
Br CH3
CH3 CH3
| |
CH3 - C - CH3 +Cl2 -------> CH3 - C - CH2Cl + HCl
| |
CH3 CH3
(2,2-диметил3-хлорпропан)
CH3 CH3
| |
CH3 - C - CH2Cl +NaOH -------> CH3 - C - CH2OH + NaCl
| |
CH3 CH3
(2,2-диметилпропанол-1)
CH3 CH3
| Kt,t |
CH3 - C - CH2OH +O2 -------> CH3 - C - COOH + H2O
| |
CH3 CH3
(2.2-диметилпропановая кислота)