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Кариночка78
@Кариночка78
July 2022
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Помогите найти интеграл. Подробно
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армения20171
$(√(x√x)-2/√x+1/x⁴)dx=$(x³/⁴)dx-
-2 *$(x^(-1/2)dx
+$(x^(-4))dx=x^(3/4+1)
/(3/4+1)-2*x^(-1/2+1)/(-1/2+1)
+x^(-4+1)/(-4+1)=
4/7 *x^(7/4)-4*x¹/²-1/3 *x^(-3)
(4*x^(7/4)/7)-4*x¹/²-1/(3*x³)
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Answers & Comments
-2 *$(x^(-1/2)dx
+$(x^(-4))dx=x^(3/4+1)
/(3/4+1)-2*x^(-1/2+1)/(-1/2+1)
+x^(-4+1)/(-4+1)=
4/7 *x^(7/4)-4*x¹/²-1/3 *x^(-3)
(4*x^(7/4)/7)-4*x¹/²-1/(3*x³)