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Aigera020
@Aigera020
August 2021
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Помогите номер 364 Упростите
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13iul
А) sin2a/sina = 2sinacosa/sina = 2cosa
б)
sin2a/2cosa = 2sinacosa/2cosa = sina
в) sin2a /(cos²a - sin²a) = sin2a / cos2a = tg 2a
г) cos2a + sin²a = cos²a - sin²a + sin²a = cos
²a
д) sin40° / 2cos20° = 2sin20°cos20° / 2cos20° = sin20
°
е) sin100° / 2cos50° = 2sin50°cos50° / 2cos50° = sin50
°
ж) (cos36° + sin²18°)/cos18° = (cos²18° - sin²18° + sin²18°)/cos²18° = cos²18°/cos²18
° = 1
з) sina / (2sin²(a/2)) = (2sin(a/2)cos(a/2))/(
2sin²(a/2)) = cos(a/2)/sin(a/2) = ctg (a/2)
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Aigera020
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Answers & Comments
б) sin2a/2cosa = 2sinacosa/2cosa = sina
в) sin2a /(cos²a - sin²a) = sin2a / cos2a = tg 2a
г) cos2a + sin²a = cos²a - sin²a + sin²a = cos²a
д) sin40° / 2cos20° = 2sin20°cos20° / 2cos20° = sin20°
е) sin100° / 2cos50° = 2sin50°cos50° / 2cos50° = sin50°
ж) (cos36° + sin²18°)/cos18° = (cos²18° - sin²18° + sin²18°)/cos²18° = cos²18°/cos²18° = 1
з) sina / (2sin²(a/2)) = (2sin(a/2)cos(a/2))/(2sin²(a/2)) = cos(a/2)/sin(a/2) = ctg (a/2)