Помогите, очень срочно нужно решение!. Created by nicesmall. algebra-ru

4sinx/cosx+cosx/sinx=2cos4x(sin²x+cos²x)/cosxsinx=2cos4x1/sinxcosx=2cos4x2/sin2x=2cos4x1/sin2x=cos4xsin2xcos4x=1,sin2x≠01){sin2x=1⇒2x=π/2+2πn⇒x=π/4+πn,n∈z{cos4x=1⇒4x=πk⇒x=πk/4,k∈zπ/4+πn=πk/41+4n=kнет решения,т.к. при любом k cлева всегда нечетное2){sin2x=-1⇒2x=-π/2+2πn⇒x=-π/4+πn,n∈z{cos4x=-1⇒4x=π+2πk⇒x=π/4+πk/2-π/4+πn=π/4+πk/2-1+4n=1+2k4n=2k+2Ответ х=π/4+πk/2,k∈z5tgx-sinx=2sin²x/2sinx/cosx-sinx=1-cosxsinx-sinx*cosx=cosx(1-cosx),cosx≠0sinx(1-cosx)-cosx(1-cosx)=0(1-cosx)(sinx-cosx)=01-cosx=0cosx=1x=πn,n∈zsinx-cosx=0/cosxtgx-1=0tgx=1x=π/4+πk,k∈zamin07amamin07amОтвет ответ ответ ответ ответ ответ ответ ответ Новые вопросы в Алгебра5. - Машина первые 4 км всего пути прошла со средней скоростью 20 км/ч, а оставшиеся 12 км пути - со срейдней скоростью 40 км/ч. Определите среднюю ск…орость машина на всем пути?СРОЧНОПитання до тесту: У ящику 4 білі кулі, 3 чорні і декілька червоних.Імовірністьтого, що навмання вийнята куля виявиться червоною, дорівнює 5/12.…Скільки червоних куль у ящику?Решите графично уровнение пожайлуста!Порівняйте з нулем значення виразу.на рисунке изображены точки со своими координатами на координатной прямой по данным рисунка укажите верное соотношение помогите пжпжпж с объяснением…ответа554 Задача, даю 40 балловЯкою є остача від ділення многочлена на двочлен(задание в файле)y=6x-2x^2найти: при каких значениях икс меньше нуляпри каких значениях икс равен нулюпжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжжрешите уравнение, срочно!!!!! ПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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Помогите, очень срочно нужно решение!...

nicesmall @nicesmall

August 2022 1 15 Report

Помогите, очень срочно нужно решение!

Answers & Comments

sedinalana

Verified answer

4
sinx/cosx+cosx/sinx=2cos4x
(sin²x+cos²x)/cosxsinx=2cos4x
1/sinxcosx=2cos4x
2/sin2x=2cos4x
1/sin2x=cos4x
sin2xcos4x=1,sin2x≠0
1){sin2x=1⇒2x=π/2+2πn⇒x=π/4+πn,n∈z
{cos4x=1⇒4x=πk⇒x=πk/4,k∈z
π/4+πn=πk/4
1+4n=k
нет решения,т.к. при любом k cлева всегда нечетное
2){sin2x=-1⇒2x=-π/2+2πn⇒x=-π/4+πn,n∈z
{cos4x=-1⇒4x=π+2πk⇒x=π/4+πk/2
-π/4+πn=π/4+πk/2
-1+4n=1+2k
4n=2k+2
Ответ х=π/4+πk/2,k∈z
5
tgx-sinx=2sin²x/2
sinx/cosx-sinx=1-cosx
sinx-sinx*cosx=cosx(1-cosx),cosx≠0
sinx(1-cosx)-cosx(1-cosx)=0
(1-cosx)(sinx-cosx)=0
1-cosx=0
cosx=1
x=πn,n∈z
sinx-cosx=0/cosx
tgx-1=0
tgx=1
x=π/4+πk,k∈z