Помогите плииз срочно надо:
а) x^2y+2xy^2+y^3
б) a^3x-4a^2x+4ax
в) -9ay^2-6ay-a
г)6bc^2-3b^2c-3c^3
а) x^2y+2xy^2+y^3=у(x^2+2xy+y^2)=y(x+y)^2
б) a^3x-4a^2x+4ax=ax(a^2-4а+4)=ax(a^2-2*а*2+2^2)=ax(a-2)^2
в) -9ay^2-6ay-a=-9a(y^2+2/3y+1/9) =-9a(y^2+2*y*(1/3)+(1/3)^2)=-9a(y+1/3)^2
г)6bc^2-3b^2c-3c^3=-3c(-2bc+b^2+c^2)=-3c(b-c)^2
а) x^2y+2xy^2+y^3=y*(y+x)^2б) a^3x-4a^2x+4ax=(a-2)^2*axв) -9ay^2-6ay-a=-a*(3y+1)^2г) 6bc^2-3b^2c-3c^3=-3c*(c-b)^2
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Answers & Comments
а) x^2y+2xy^2+y^3=у(x^2+2xy+y^2)=y(x+y)^2
б) a^3x-4a^2x+4ax=ax(a^2-4а+4)=ax(a^2-2*а*2+2^2)=ax(a-2)^2
в) -9ay^2-6ay-a=-9a(y^2+2/3y+1/9) =-9a(y^2+2*y*(1/3)+(1/3)^2)=-9a(y+1/3)^2
г)6bc^2-3b^2c-3c^3=-3c(-2bc+b^2+c^2)=-3c(b-c)^2
а) x^2y+2xy^2+y^3=y*(y+x)^2
б) a^3x-4a^2x+4ax=(a-2)^2*ax
в) -9ay^2-6ay-a=-a*(3y+1)^2
г) 6bc^2-3b^2c-3c^3=-3c*(c-b)^2