Ответ:
Объяснение:
4. (1-2cos²α)/(sinα×cosα) = tgα - ctgα ;
(1-2cos²α)/(sinα×cosα) = (sin²α+cos²α-2cos²α)/(sinα×cosα)=
=(sin²α-cos²α)/(sinα×cosα) = sin²α/(sinα×cosα) - cos²α/(sinα×cosα) =
= sinα/cosα - cosα/sinα = tgα - ctgα ;
6. (1-cosα)×(1+cosα) × ctg²α = (1-cos²α) × ctg²α = sin²α × (cos²α/sin²α)=
= cos²α.
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Answers & Comments
Ответ:
Объяснение:
4. (1-2cos²α)/(sinα×cosα) = tgα - ctgα ;
(1-2cos²α)/(sinα×cosα) = (sin²α+cos²α-2cos²α)/(sinα×cosα)=
=(sin²α-cos²α)/(sinα×cosα) = sin²α/(sinα×cosα) - cos²α/(sinα×cosα) =
= sinα/cosα - cosα/sinα = tgα - ctgα ;
6. (1-cosα)×(1+cosα) × ctg²α = (1-cos²α) × ctg²α = sin²α × (cos²α/sin²α)=
= cos²α.