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Anastasiya21126
@Anastasiya21126
July 2022
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Помогите подалуйста, СРОЧНО НУЖНО!!!
Решите уравнение:
(2x^2-x+1)^2-4x^2=1-2x
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dasdasfa
((2x^2)-(x-1))^2-4x^2=1-2x
4x^4-2*(2x^2)*(x-1)+(x-1)^2 -4x^2=1-2x
4x^4-4x^3+4x^2+x^2-2x+1-4x^2=1-2x
4x^4-4x^3+x^2=0
x^2 (4x^2-4x+1)=0
x^2=0 ili 4x^2-4x+1=0
x=0 (2x-1)^2=0
2x-1=0
x=1/2; x=0,5
Ответ. 0;0,5
1 votes
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Answers & Comments
4x^4-2*(2x^2)*(x-1)+(x-1)^2 -4x^2=1-2x
4x^4-4x^3+4x^2+x^2-2x+1-4x^2=1-2x
4x^4-4x^3+x^2=0
x^2 (4x^2-4x+1)=0
x^2=0 ili 4x^2-4x+1=0
x=0 (2x-1)^2=0
2x-1=0
x=1/2; x=0,5
Ответ. 0;0,5