Помогите пожалуйста, 60 баллов!. Created by RiosLorenzoAlexandra. algebra-ru

Помогите пожалуйста, 60 баллов!...

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$\sqrt{3}Sin^{2}x+2SinxCosx=0\\\\Sinx(\sqrt{3}Sinx+2Cosx)=0\\\\1)Sinx=0\\\\x=\pi n,n\in Z\\\\2)\sqrt{3}Sinx+2Cosx=0|:Cosx\neq 0\\\\\sqrt{3}tgx+2=0\\\\tgx=-\frac{2}{\sqrt{3} }\\\\x=arctg(-\frac{2}{\sqrt{3} })+\pi n,n\in Z\\\\x=-arctg(\frac{2}{\sqrt{3} } )+\pi n,n\in Z$

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cambogiyt

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