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Ustailia
@Ustailia
July 2022
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Помогите, пожалуйста, алгебра 7 класс!
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zhenyaM2002
Verified answer
{ (c+1) / (2a - 4) = 1/2
{(5a +c) /(3a+6) = 1
знаменатели дробей не должны быть равны 0 :
2а - 4 ≠ 0 ; а ≠ 2
3а + 6≠ 0 ; а ≠ - 2
{ 2(c+1) = 1 *(2a - 4)
{ 5a + c = 1 *(3a + 6)
{ 2c + 2 = 2а - 4
{ 5a + c = 3a + 6
{ 2c - 2а = - 4 - 2
{ 5a +c - 3a = 6
{ 2c - 2a = - 6
{ c + 2a = 6
метод сложения:
2с - 2а + с + 2а = - 6 + 6
3с = 0
с = 0
0 + 2а = 6
2а = 6
а = 6 : 2
а = 3
проверим:
( 0 + 1) /(2*3 - 4) = 1/(6 - 4) = 1/2
(5*3 +0)/(3*3 + 6) = 15/(9+6) = 15/15 = 1
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Answers & Comments
Verified answer
{ (c+1) / (2a - 4) = 1/2{(5a +c) /(3a+6) = 1
знаменатели дробей не должны быть равны 0 :
2а - 4 ≠ 0 ; а ≠ 2
3а + 6≠ 0 ; а ≠ - 2
{ 2(c+1) = 1 *(2a - 4)
{ 5a + c = 1 *(3a + 6)
{ 2c + 2 = 2а - 4
{ 5a + c = 3a + 6
{ 2c - 2а = - 4 - 2
{ 5a +c - 3a = 6
{ 2c - 2a = - 6
{ c + 2a = 6
метод сложения:
2с - 2а + с + 2а = - 6 + 6
3с = 0
с = 0
0 + 2а = 6
2а = 6
а = 6 : 2
а = 3
проверим:
( 0 + 1) /(2*3 - 4) = 1/(6 - 4) = 1/2
(5*3 +0)/(3*3 + 6) = 15/(9+6) = 15/15 = 1