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lena270699
@lena270699
July 2022
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помогите пожалуйста. формулы двойного угла
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Nika14042014
По формуле sin a = 2 tg( a\2 ) \ 1+tg 2 a\2 sin2x=2tgx\1+tg2X=2*3\1+9
sin2x=0,6 cos2x=0,8 sin4x=2*0,6*0,8=0,96
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sin2x=0,6 cos2x=0,8 sin4x=2*0,6*0,8=0,96