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kamenkoliza
@kamenkoliza
July 2022
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Помогите пожалуйста
х^2+8x+15=(x+3)(x-a)
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musician19
х²+8x+15=(x+3)(x-a)
х²+8х+15=х²+3х-ха-3а
5х+ха+15+3а=0
х(5+а)+3(5+а)=0
(5+а)(х+3)=0
при а=-5 х(-∞;+∞) - любое число
при а≠-5 х=-3
1 votes
Thanks 1
miron2077
Verified answer
X^2+8x+15=(x+3)(x-a)
По формуле:
x^2+bx+c=(x-x1)(x-x2)
x1=-3 x2=a
x1*x2 =15
-3a=15
a=15/(-3)
a= -5
Ответ: -5
0 votes
Thanks 0
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Answers & Comments
х²+8х+15=х²+3х-ха-3а
5х+ха+15+3а=0
х(5+а)+3(5+а)=0
(5+а)(х+3)=0
при а=-5 х(-∞;+∞) - любое число
при а≠-5 х=-3
Verified answer
X^2+8x+15=(x+3)(x-a)По формуле:
x^2+bx+c=(x-x1)(x-x2)
x1=-3 x2=a
x1*x2 =15
-3a=15
a=15/(-3)
a= -5
Ответ: -5