Ответ:
5
a)(-1/5,1)
б)(−∞,−92]∪[2,∞)
6
a)(−∞,−3)∪(2,∞)
б)[−5,−1]
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Ответ:
5
a)(-1/5,1)
б)(−∞,−92]∪[2,∞)
6
a)(−∞,−3)∪(2,∞)
б)[−5,−1]