помогите, пожалуйста, решить неравенство. Created by TalisDarya. algebra-ru

помогите, пожалуйста, решить неравенство...

Universalka

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(2x - 7)² ≥ (6x + 1)²

(2x - 7)² - (6x + 1)² ≥ 0

(2x - 7 + 6x + 1)(2x - 7 - 6x - 1) ≥ 0

(8x - 6)(- 4x - 8) ≥ 0

8 * ( - 4) *(x - 0,75)(x + 2) ≥ 0 |: (- 32)

(x - 0,75)(x + 2) ≤ 0

+ - +

___________[-2]__________[0,75]___________

//////////////////////////////

x ∈ [- 2 ; 0,75]

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NNNLLL54

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$(2x-7)^2\geq (6x+1)^2\; \; \Rightarrow \\\\(2x-7)^2-(6x+1)^2\geq 0\\\\(2x-7-6x-1)\cdot (2x-7+6x+1)\geq 0\\\\(-4x-8)(8x-6)\geq 0\\\\-4\cdot (x+2)\cdot 2(4x-3)\geq 0\\\\(x+2)(4x-3)\leq 0\\\\+++[-2\, ]---[\, \frac{3}{4}\, ]+++\\\\x\in [-2\, ;\, \frac{3}{4}\, ]$

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