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Krodu
@Krodu
July 2022
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Помогите, пожалуйста, решить тригонометрическое уравнение:
1 - cos6x = tg3x
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Эль96
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n∈Z
8 votes
Thanks 11
rudlarpar
2sin^2(3x)-sin(3x)/cos(3x)=0 cos(3x) не равно 0, тогдa 2sin^2(3x) cos(3x)-sin(3x)=0 sin 3x(2sin 3x cos 3x-1)=0 sin 3x=0 3x=pik x=pik/3 sin 6x-1=0 sin 6x=1 6x=pi/2+2pin x=pi/12+pin/3
2 votes
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n∈Z